Where is the night crew???

Joined: 13 Jun 2005 Location: Riverina

soft

Joined: 09 Mar 2004 Location: queensland

j-top paj wrote:

mnemonix wrote:

"just one more shandy and sleep by midnight crew".

got a big ride on in the morning,
riding down to canberra via batemans and then back up over to mosman afterwards...

night all

batemans bay is my home town Very Happy

anyways i got work in the morning

Posted: Sat Aug 16, 2008 11:52 pm

I'm on $51hr surfing outers Laughing

Joined: 09 Mar 2004 Location: queensland

longlux wrote:

I'm on $51hr surfing outers Laughing

wow ... the high life
using a PDA while train driving cant be good can it?

Joined: 30 Jan 2005 Location: Newie

Whats happenin' blokes? Shandy sipping again?

Posted: Sun Aug 17, 2008 2:17 am

ofr57 wrote:

longlux wrote:

I'm on $51hr surfing outers Laughing

wow ... the high life
using a PDA while train driving cant be good can it?

I was in the office Rolling Eyes

Joined: 09 Mar 2004 Location: queensland

longlux wrote:

ofr57 wrote:

longlux wrote:

I'm on $51hr surfing outers Laughing

wow ... the high life
using a PDA while train driving cant be good can it?

I was in the office Rolling Eyes

ah ok

evening Very Happy

cant beat maths at midnight Rolling Eyes

Joined: 22 Oct 2006 Location: yallourn north,victoria

hey crew

wtf is happening armsup

Joined: 29 Aug 2005 Location: western shitney

went for a big ride on the weekend

some pics

Joined: 29 Aug 2005 Location: western shitney

that was at the nattai lookout over burragorang

Joined: 09 Mar 2004 Location: queensland

tna racing wrote:

hey crew

wtf is happening armsup

MATHS

simplify
[(2xz^-2)^3(x^-2z)/2xz^2]^4 Confused

Joined: 29 Aug 2005 Location: western shitney

90 bikes were counted at one stage but i think there was more as a few bikes turned off along the way

Joined: 09 Mar 2004 Location: queensland

how long did it take ya jtop? where the hell is burragorang

Joined: 22 Oct 2006 Location: yallourn north,victoria

ofr57 wrote:

tna racing wrote:

hey crew

wtf is happening armsup

MATHS

simplify
[(2xz^-2)^3(x^-2z)/2xz^2]^4 Confused

obviously makes out this equation
=ajblowsthemanflutewithjtophumpinghisgoat

done, clearly that's the answer

Joined: 29 Aug 2005 Location: western shitney

that was sundays ride,
its the warragamba dam.

from windsor to nattai was a slow trip because it was such a large group and everyone was behaving themselves.

from nattai to appin was a bit better as i overtook most of the slower/new riders in the twisties Very Happy

hit $2.40 at one stage

Joined: 29 Aug 2005 Location: western shitney

the ride up from the gong up mt keira was fun Twisted Evil

i let my mate go in front as he was on his own and i was riding 2 up,
he was on a brand new VFR with VTEC and still couldnt pull away from me Laughing

got to the top and he couldnt beleive that an "old" bike with 2 people on it could ride so quick Laughing

a few other times throughout the day i showed him what a pre VTEC VFR can do Twisted Evil

Joined: 29 Aug 2005 Location: western shitney

saturdays ride was fun,
rode from sutherland to robo pie shop to meet up with the canberra riders (and one that was spose to be coming from melboring but got a flat at albury)
then we went down through kangaroo valley to nowra for fuel and onto batemans bay,
then up to braidwood and across to goulburn and back to shitney

Joined: 29 Aug 2005 Location: western shitney

Joined: 09 Mar 2004 Location: queensland

WAKE UP NIGHT CREW Very Happy

Joined: 22 Oct 2006 Location: yallourn north,victoria

im awake

Joined: 09 Mar 2004 Location: queensland

tna racing wrote:

im awake

great i need your help with this maths again Laughing

Joined: 22 Oct 2006 Location: yallourn north,victoria

ok. whats the equation Wink

Joined: 09 Mar 2004 Location: queensland

[((2xz^-2)^3 (x^-2z)) / 2xz^2]^4 The Finger

has to be simplyfied Confused

Joined: 22 Oct 2006 Location: yallourn north,victoria

im only new to hard maths Laughing

Joined: 21 Aug 2006 Location: nowhere interesting

ofr57 wrote:

[((2xz^-2)^3 (x^-2z)) / 2xz^2]^4 The Finger

has to be simplyfied Confused

Answer = 256 z^(-28)

True ... it is Smile

Joined: 09 Mar 2004 Location: queensland

Moph wrote:

ofr57 wrote:

[((2xz^-2)^3 (x^-2z)) / 2xz^2]^4 The Finger

has to be simplyfied Confused

Answer = 256 z^(-28)

True ... it is Smile

i got 256z^(-12) Confused

Joined: 22 Oct 2006 Location: yallourn north,victoria

i got 256^z(-15)

Joined: 21 Aug 2006 Location: nowhere interesting

Hmmm don't think so. Expanding it out.....

[((2xz^-2)^3 (x^-2z)) / 2xz^2]^4

=

{ [(2^3)(x^3)(z^-6)] * [(x^-2)(z)] * [(2^-1)(x^-1)(z^-2)] }^4

=

{ (2^3 * 2^-1)(x^3 * x^-2 * x^-1)(z^-6 * z * z^-2) }^4

=

{ (2^2)(z^-7) }^4

=

(2^8)(z^-28)

=

256z^-28

Just checked it for x = 3, z = 9 in Excel and it works.

Joined: 21 Aug 2006 Location: nowhere interesting

Trick is that if you're multiplying two exponents, you add the two together:

(x^10)(x^-3) = x^(10-3) = x^7

If you're finding the exponent of a exponent, you multiply the exponents:

(x^10)^3 = x^(10 * 3) = x^30

And where you are dividing by a term, just inverse the exponents of each term to move them to the numerator and make them easier (more logical) to work with:

1 / (2xz^2) = 1 / [(2^1)(x^1)(z^2)] = (2^-1)(x^-1)(z^-2)

Of course a single add / subtract operation in there somewhere can stuff all that up Very Happy

Joined: 09 Mar 2004 Location: queensland

oh ok ... what did i do wrong? i did this
[((2xz^-2)^3 (x^-2z)) / 2xz^2]^4

=(((2xz^-2)^3)^4 ((x^-2z)^4)) / (2xz^2)^4

= ((2xz^-2)^12) (x^-8z^4)) / (16x^4z^8)

= (4096x^12z^-24) * (x^-8z^4)/ 16x^4z^-8

= 4096x^4z^-20/16x^4z^-8

= 256z^-12

= 256/z^12

are you a maths teacher.... because you should be armsup

better then my uni lecturer for sure